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CTET Paper I (Classes I to V) 14 Dec 2024 Shift 2 Solved Paper

Question : 53 of 150

Marks: +1, -0

The value of

\frac{4}{7}+\frac{5}{14}-\frac{7}{8}

is :

Solution:

Concept:

To add or subtract fractions, first find a common denominator (the LCM of the denominators).

Explanation:

The denominators are 7, 14, and 8.

LCM of 7, 14, and 8 is

56

Convert each fraction to denominator 56:

\frac{4}{7} = \frac{4 \times 8}{56} = \frac{32}{56}

\frac{5}{14} = \frac{5 \times 4}{56} = \frac{20}{56}

\frac{7}{8} = \frac{7 \times 7}{56} = \frac{49}{56}

Now compute:

\frac{32}{56} + \frac{20}{56} - \frac{49}{56} = \frac{32 + 20 - 49}{56} = \frac{52 - 49}{56} = \frac{3}{56}

Answer:

\frac{3}{56}

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