Let's denote the three consecutive integers as x,x+1, and x+2. According to the given conditions: 3x is the result when the first integer is multiplied by 3 . 5(x+1) is the result when the second integer is multiplied by 5 . 2(x+2) is the result when the third integer is multiplied by 2 . The sum of these results is 99 : 3×x+5×(x+1)+2×(x+2)=99 Now, let's solve this equation: 3x+5x+5+2x+4=99 10x+9=99 10x=90 x=9 So, the three consecutive integers are 9,10 , and 11 . Now, the sum of the original first and third integers is 9+11=20.