Given, resistance of the galvanometer, G=40Ω Current in the galvanometer, Ig=10mA=10×10−3A Maximum reading of voltmeter, V=50V The galvanometer can be converted into voltmeter by connecting a shunt resistance (S) in the series. Voltage in the voltmeter is given by V=Ig(G+R) ∴50=10×10−3(40+R) ⇒5000=40+R ⇒R=4960Ω