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COMEDK 2025 Morning Solved Paper

Question : 104 of 180

Marks: +1, -0

Choose the correct statement.

A solution formed by adding Carbon di-sulphide to Acetone forms a maximum boiling azeotrope.
Hypotonic solution is more concentrated with respect to the other solution separated by a semi permeable membrane
For a solvent, $\quad K_b=\frac{R \times M_1 \times T_b^2}{1000 \times \Delta \text{Hvap}}$
$\left(\mathrm{R}=\mathrm{Gas}\right.$ constant, $M_1=$ Molar mass of solvent, $T_b = B \cdot P$ of the solvent $)$
A 1.0 molal solution of Glucose in water is more concentrated than 1.0 M glucose solution in the same solvent.

Validate

Solution:

Concept:

Understanding colligative properties and the correct formula for the ebullioscopic constant.

Explanation:

• Option A is false: Carbon disulphide and acetone form a minimum boiling azeotrope, not a maximum boiling one.

• Option B is false: A hypotonic solution has a lower solute concentration (and lower osmotic pressure) compared to the other solution separated by a semipermeable membrane.

• Option C is correct: The ebullioscopic constant

K_b

is derived from the Clausius–Clapeyron relation and is given by

K_b = \frac{R M_1 T_b^2}{1000 \Delta H_{\text{vap}}}

, where

R

is the gas constant,

M_1

is the molar mass of the solvent (in g/mol),

T_b

is the boiling point of the solvent (in K), and

\Delta H_{\text{vap}}

is the molar enthalpy of vaporization (in J/mol).

• Option D is false: A 1.0 molal (

\text{mol kg}^{-1}

) solution of glucose in water has a volume greater than 1 L, so its molarity is less than 1.0 M. Therefore, it is less concentrated than a 1.0 M glucose solution.

Answer:

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