COMEDK 2025 Evening Solved Paper

Concept:The integrand simplifies to a constant value on the integration interval because the absolute value can be removed by checking the sign of $x-3$.Explanation:The expression $\frac{|x-3|}{x-3}$ equals $1$ when $x-3>0$ (i.e., $x>3$) and equals $-1$ when $x-3<0$ (i.e., $x<3$).The integration limits are from $-2$ to $2$. Over this entire interval, $x-3$ is always negative, so $|x-3| = -(x-3)$ and $\frac{|x-3|}{x-3} = -1$.Hence, the integral becomes $\int_{-2}^{2} (-1) \, dx$.Evaluating: $(-1) \times (2 - (-2)) = (-1) \times 4 = -4$.Answer:$-$4 (Option A).