COMEDK 2025 Afternoon Solved Paper

Concept:Both statements A and D contain incorrect orders of boiling points and nucleophilic reactivity, respectively.Explanation:Option A lists the boiling point order as Methoxyethane $<$ Propanone $<$ Propanal $<$ Propan-1-ol.But the correct order is Methoxyethane ($7.4\,{}^{\circ}\text{C}$) $<$ Propanal ($49\,{}^{\circ}\text{C}$) $<$ Propanone ($56\,{}^{\circ}\text{C}$) $<$ Propan-1-ol ($97\,{}^{\circ}\text{C}$).So A is incorrect because propanone boils higher than propanal.Option D states reactivity toward nucleophiles: Methanal $>$ Di‑tert‑butyl ketone $>$ Benzaldehyde $>$ Acetophenone.The correct order is Methanal $>$ Benzaldehyde $>$ Acetophenone $>$ Di‑tert‑butyl ketone.Di‑tert‑butyl ketone is least reactive due to extreme steric hindrance, and benzaldehyde is more reactive than acetophenone because the phenyl group withdraws electrons.Thus D is also incorrect.Option B (hybridisation change in HCN addition) and Option C (Wolff‑Kishner reduction of acetone to propane) are both correct.Answer:Statements A and D are the incorrect statements.