CMAT Exam 2023 Shift 2 Solved Paper

Statement I:Let the actual time taken by Ravi to reach the college be ' $t$ '.If Ravi travels at a speed of $5 \text{ km/hr}$, time taken is $t + \frac{10}{60}$ If Ravi travels at a speed of $6 \text{ km/hr}$, time taken is $t - \frac{4}{60}$ Distance $=$ speed*time $5t + \frac{50}{60} = 6t - \frac{24}{60}$$t = \frac{74}{60}$Distance $(P) = 5 \left(\frac{74}{60} + \frac{10}{60}\right) = 5 \left(\frac{84}{60}\right) = 7 \text{ km}$Therefore, statement I is incorrect.Statement II:Let the speed of Babita be $3x$.The speed of Amit is $7x$.B covers distance $y$.In the same time, A should cover $80+y$.$\frac{y}{3x} = \frac{80+y}{7x}$$7y = 240 + 3y$$4y = 240$$y = 60$Total distance $= 80 + 60 = 140 \text{ m}$Therefore, statement II is correct.The answer is option D.