CMAT 2013 Solved Question Paper

(c) Since, in the numerator of the product of the expression, there will be 2 zeroes at the end and these two zeroes will be cancelled by 2 zeroes of the denominator. Hence finally, we get a non-zero unit digit in the expression.Now, $1\times 2\times 3\times 4$ × $\frac{5\times 6\times 7\times 8\times 9\times 10}{100}$ = $\frac{1\times 2^{8}\times 3^{4}\times 5^{2}\times 7^{1}}{5^{2}\times 2^{2}}$ = $1 \times 2^{6}\times 3^{4}\times 7$Therefore, the unit digit of the given expression will be same as that of = $1 \times 2^{6}\times 3^{4}\times 7$Multiplication is $1 \times 2^{6}\times 3^{4}\times 7$ is ‘36288’.Now, the unit digit is '8‘