CGPET 2019 Solved Paper

In given reaction,
‌ZXA

α

───▸

‌Z−2YA−4

β

───▸

‌Z−1KA−4

γ

───▸

‌Z−1KA−4 In above reaction, in first atomic number z decreases by 2 and mass number A decreases by 4.
So, α -particle emitted.
In second step, atomic number (z−2) increases by 1 and man number (A−4) remains same hence β-particle emitted.
In third step, atomic number (z−1) and mans number (A−4) remain same.
Hence γ -particle emitted.
Hence, radioactive radiations are emitted in sequence of α,β,γ