(i) CH3−C≡CH can provide white ppt. with Ag2O, as it can give aldehyde as intermediate product. (ii) CH3−C≡CH can give aldehyde on treatment with Hg2+∕H+, which on reduction with NaBH4 gives 2° -alcohol. The 2° -alcohol gives blue colour with ether during victor meyer test. (i) CH3−
C
′A′
≡CH
Ag2O
────▸
CH3−CH2−CHO (ii) (I) CH3−C≡CH
Hg2+∕H+
────▸
CH3-CH2−CHO (II) CH3−CH2−CHO
NaBH4
────▸
Reduction
CH3−
CH
|
OH
−CH3
(2°−alcohol)
(III) CH3−
CH
|
OH
−CH3
Victor meyer
────▸
test
blue colour with ether. Hence, (b) is the correct option.