Nessler's reagent is K2HgI4. It is a basic solution of potassium mercuric iodide which gives reddish brown ppt. of millon's base [H2N−HgO−HgI] with NH3, as follows NH3+2K2HgI4+3KOH→H2N−HgO−HgI↙(lodideofmillon′sbase)Brownppt.+7KI+2H2O Thus, it can give [HgI4]2− ions so, option (d) is the correct answer.