I=โซe2xโsec2x(1+4tan2x)dx=โซe2xโ(sec2x+4tan2xโ sec2x)dx Let 2xโ=t,ย x=2t,ย dx=2dtโดI=2โซet(sec4t+4tan4tโ sec4t)dt .......(i) We know, โซex(f(x)+fโฒ(x))dx=exf(x)+C .......(ii) and dxdโ(sec4x)=4sec4xtan4x From Eqs. (i) and (ii), we get =2[etsec4t+Cโฒ]=2etsec4t+2Cโฒ Put the value of t, we get =2ex/2sec4โ (2xโ)+2cโฒ=2ex/2sec2x+C[ Here 2Cโฒ=C]