The wavelength of light emitted by the star =5896Å λ=5896×10−10m Speed v=3600km∕s=3600×103m∕s From Doppler's law in light shift in wavelength Δλ=
v
C
.λ(c=3×108m∕s, speed of light) =
3600×103×5896×10−10
3×108
m =
12×5896×10−10
103
Δλ=70.752Å The wavelength of light observed on each will increase by 70.75Å