{NO}₃^{-}is detected by ring test. Ring formed has formula

Correct Answer is : [Fe(H2O)5⋅NO]2+≤ft[{Fe}({H}₂{O})₅·{NO}]²+}[Fe(H2O)5⋅NO]2+

≤ft[{Fe}({H}₂{O})₅·{NO}]²+}

Correct Answer is : [Fe(H2O)5⋅NO]2+≤ft[{Fe}({H}₂{O})₅·{NO}]²+}[Fe(H2O)5⋅NO]2+

Test Index

CGPET 2012 Solved Paper

Section: Chemistry

Question : 51 of 150

Marks: +1, -0

\mathrm{NO}_3^{-}

Solution:

When nitrate salt is treated with dil

\mathrm{HCl}

and freshly prepared solution of

\mathrm{FeSO}_4

and some conc.

\mathrm{H}_2\mathrm{SO}_4

is added by the sides of test tube, a brown ring of ferrous nitrososulphate is formed. It is called ring test of

\mathrm{NO}_3^{-}

ion.

6\mathrm{FeSO}_4+2\mathrm{HNO}_3+3\mathrm{H}_2\mathrm{SO}_4 \rightarrow 3\mathrm{Fe}_2(\mathrm{SO}_4)_3

+2\mathrm{NO}+4\mathrm{H}_2\mathrm{O}

\left[\mathrm{Fe}(\mathrm{H}_2\mathrm{O})_6\right]\mathrm{SO}_4+\mathrm{NO} \rightarrow \left[\mathrm{Fe}(\mathrm{H}_2\mathrm{O})_5\mathrm{NO}_2\right]\mathrm{SO}_4.

+\mathrm{H}_2\mathrm{O}

\;\text{ or }\;

\left[\mathrm{Fe}(\mathrm{H}_2\mathrm{O})_5\mathrm{NO}\right]^{2+}

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