⇒‌(x−6)(x−2)‌=0 ⇒x‌=2,6 ‌ and ‌‌y2−14y+45‌=0 ⇒‌(y−9)(y−5)‌=0 ⇒y‌=5,9 Firstly, we draw the lines x=2,x=6 and y=5,y=9. The intersection of these lines formed a square ABCD. A circle is circumscribed on the square ABCD whose centre is (4,7).