Let PQ and RS be two parallel chords of the circle on the opposite sides of the diameter AB and PQ=16cm
Now, PN =8 (Since ON is the perpendicular bisector) In ΔPON, ON2=OP2−PN2 =(17)2−(8)2=289−64=225 or ON=15⇒ ∴ OM=23−15=8 In ΔORM, RM2=OR2−OM2=172−82=289−64=225 or RM=15⇒RS=15×2=30cm