Let us assume that the accident happens at point A.
Hence PA and AQ would be the distances covered by the train from P to A and A to Q respectively.
Let the speed (in km/min) before and after the accident be V and ‘u'.
Total time taken by the train had the accident not taken place
=vPQ​=v(PA+AQ)​Total time taken by the train due to accident
=vPA​+UAQ​=vPQ​+16=vPA​+vAQ​+16Hence,
AQ(u1​−v1​)=16 ...(i)
From Statement A:In this case let us assume that the accident happens at point B Following a similar method as mentioned above we get:
BQ
(u1​−v1​)=21or
(AQ+10)(u1​−v1​)=21...(ii)
From (i) and (ii):
AQ = 32 km and hence, PQ = 30 + 32 = 62 km
From Statement B:In this case let us assume that the accident happens at point C. Following a similar method as mentioned above we get:
CQ(u1​−v1​)=20(u1​−v1​)=12...(iii)
From (i) and (iii):
AQ=380​ km and hence,
PQ=30+380​=3170​ kmSo the question can be answered by using either of the statements alone.