CAT Exam Model Paper 3 with solutions for free online practice

(b) Length of the track = $2 \times \frac{22}{7} \times 175 = 1100$m Distance to be covered for the first meeting = 550 m Speed of Akkal =$\frac{1100}{100}=11$m/s Speed of Bakkal = $\frac{1100}{50}$ = 22 m/sTime taken from the start of the first meeting =$\frac{550}{11+22}=\frac{50}{3}$sTime taken for Akkal and Bakkal to meet again at Love point = LCM of time taken by them to go around the track once.= LCM of $\frac{1100}{11}$ and $\frac{1100}{22}$= LCM of 100 and 50= 100 sSo, the total required time = $\frac{50}{3}+100+100$$=\frac{650}{3}=216\frac{2}{3}$s