CAT Exam 2021 Slot 2 Solved Paper

Case 1 :
x≥

40

3

We get : 3x−20+3x−40=20
6x=80
x=

80

6

=

40

3

=13.33
Case 2 :

20

3

≤x<

40

3

We get : 3x−20+40−3x=20
We get 20 = 20
So, we get :
xε[

20

3

,40,3]
Case 3:
x<

20

3

We get 20-3x + 40-3x = 20
40=6x
x=

20

3

but this is not possible
so we get from case 1,2 and 3
Now looking at options
we can say only option C satisfies for all x .Hence 7<x<12.