Let n,s,d and t be the number of students who likes none of the drinks, exactly one drink, exactly 2 drinks and all three drinks, respectively. It is given, n+s+d+t=100...(i) s+2d+3t=73+80+52 s+2d+3t=205...(ii) Eqs(ii)−(i), we get: d+2t−n=105 Maximum value t can take is 52 , i.e. t=52,d=1 and n=0 Minimum value t can take is 5 , i.e. t=5,d=95 and n=0...[This‌also‌satisfies‌equation(i)] Difference =52−5=47 The answer is option A.