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CAT 2022 Slot 1 Paper

Question : 46 of 66

Marks: +1, -0

Solution:

Let the original number of students be '

n

' whose average weight is

x

Let the number of students added be '

m

' and the average weight will be

x+3

We need to find the value of

n:m

It is given, average weight of students in a class increased by 0.6 after new students are added.

Therefore,

\frac{n x+m(x+3)}{n+m}=x+0.6

n x+m x+3 m=m x+n x+0.6 n+0.6 m

2.4 m=0.6 n

4 m=n

\frac{n}{m}=\;\frac{4}{1}

The answer is option C

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