Given the circle is inscribed in the rhombus of diagonals 12 and 16 . Let O be the point of intersection of the diagonals of the rhombus. Then, OE (radius) ⟂ DC. Also DC=√62+82=10 As area of ∆ODC should be the same, we have, ‌
1
2
×6×8=‌
1
2
×OE×10 ⇒OE=4.8 ∴ Required ratio of areas =‌