f(x)=min(2x2,52−5x) The maximum possible value of this function will be attained when 2x2=52−5x. (2x+13)(x−4)=0 ⇒x=‌
−13
2
or x=4 Since x has to be positive integer, we can discard the case x=‌
−13
2
. x=4 is the point at which the function attains the maximum value. putting x=4 in the original function, we get, 2x2=2*42=32. Or the maximum value of f(x)=32