Area of the box = area (2 hexagons) + area (6 rectangles). =6‌‌
√3
4
a2×2+6×ah =3√3a2+6ah In the revised box, the height becomes = 2h New area = 6‌‌
√3
4
a2×2+6×a×2h =3√3a2+12ah Area has increased by 50% ⇒ New area = 1.5 x (old area) ⇒(3√3a2+6ah)15=3√3a2+12ah ⇒3√3a2×15+9ah=3√3a2+12ah ⇒3√3a2×05=3ah ⇒‌‌