In Young's double slit experiment within a medium with a refractive index of 1.33 , the maximum intensity is represented as
I0.
To find the intensity at a point on the screen where the path difference between the light from the slits is
, follow these steps:
Path Difference: Given as
∆x=.
Phase Difference Calculation:
φ=()×∆xSubstituting the given path difference:
φ=×=Intensity Calculation: The intensity at any point on the screen with a phase difference
φ is given by:
I=I0cos2()Substituting the phase difference:
I=I0cos2()Simplifying further:
I=I0cos2()I=I0()2I=Thus, the intensity at the specified point on the screen is
.