Let r be the radius of the sphere and Δr be the error in measuring the radius. Then, r=9‌cm and Δr=0.03‌cm Let V be the volume of the sphere. Then, V=
4
3
πr3 ⇒
dV
dr
=4πr2 ⇒ (
dV
dr
)r=9=4π×92=324π Let ΔV be the error in V due to error Δr in r. Then, ΔV=