Reflection of the line \frac{x-1}{-1}=\frac{y-2}{3}=\frac{z-4}{1} in the plane x+y+z=7 is

Correct Answer is : x−1−3=y−21=z−4−1

\frac{x-1}{3}=\frac{y-2}{1}=\frac{z-4}{1}

\frac{x-1}{-3}=\frac{y-2}{-1}=\frac{z-4}{1}

\frac{x-1}{-3}=\frac{y-2}{1}=\frac{z-4}{-1}

\frac{x-1}{3}=\frac{y-2}{1}=\frac{z-4}{1}

Test Index

BITSAT 2019 Slot 2 Solved Paper

Section: Mathematics

Question : 149

Total: 150

Reflection of the line

in the plane x+y+z=7 is

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