The given line is 12 (x + 6) = 5(y – 2) ⇒ 12x + 72 = 5y – 10 or 12x – 5y + 72 + 10 = 0 ⇒ 12x – 5y + 82 = 0 The perpendicular distance from (x1,y1) to the line ax + by + c = 0 is
(ax1+by1+c)
√a2+b2
The point (x1,y1) is (–1, 1), therefore, perpendicular distance from (–1, 1) to the line 12x - 5y + 82 = 0 =