GIVEN: The vertices of the parallelogram = A(1, 2), B(a, -26), C(13, -14) and D(6, 14) CONCEPT: Using the distance formulae we will equate the parallel sides of the parallelogram. FORMULAE USED: D = √((x2−x1)²+(y2−y1)²) CALCULATION: AB = DC ⇒ {(a−1)2+(−26−2)2} = {(6−13)2+(14−(−14))2} ⇒ (a−1)2 + 784 = 49 + 784 ⇒ (a−1)2 = 49 ⇒ a - 1 = 7 ∴ a = 8