Concept:Use the identity tanA⋅cotA=1 and square the given equation to find tan2A+cot2A.Explanation:Given: tanA+cotA=2Square both sides:(tanA+cotA)2=22tan2A+cot2A+2tanA⋅cotA=4Since tanA⋅cotA=1, we get:tan2A+cot2A+2(1)=4tan2A+cot2A+2=4tan2A+cot2A=2Now multiply by 2:2(tan2A+cot2A)=2×2=4Answer:The required value is 4, so the correct option is B.