x, y, z are positive integers.I. Given : x + y + z is even.
⇒x+y+z=2,4,6,8,10,12,14,16,…
Of these, only multiples of 14 are divisible by 7 while others are not.∴ I alone is not sufficient.II. Given : x=4y−11 and z=2y+4.Adding the two we get,x+z=6y−7⇒x+y+z=7y−7=7(y−1)Since 7 is a factor, x+y+z is divisible by 7.∴ II alone is sufficient.