I Given : secθ+cscθ=5⇒cosθ1+sinθ1=5⇒sinθ+cosθ=5sinθcosθ⇒sinθ+cosθ=25sin2θSince sin 2θ or sinθ or cosθ is not given, we can’t determine sinθ + cosθ.∴ I alone is not sufficientII. Given : sin2θ=21⇒ 2θ = 30° or 150°[Sine is positive in QI and QII]⇒ θ = 15° or 75°sin15∘+cos15∘=sin15∘+sin75∘Also, sin75∘+cos75∘=sin75∘+sin15∘Hence, sinθ+cosθ can be uniquely determined.∴ II alone is sufficient.Aliter : sinθ+cosθ=sinθ+cosθ2
=1+2sinθcosθ=1+sin2θ=1+21
23we discard –23 as θ lies in the first quadrant.∴ II alone is sufficient.