Given: x and y are real numbers.I. Given: x+y=16There are two unknowns and only one equation. Further, x and y being real numbers, we can have infinite number of solutions.∴ Ι alone is not sufficientII. Given: x2+y2=160Similarly, II alone is not sufficient.I&II. x+y=16,x2+y2=160(x+y)2=x2+y2+2xy.So we can find xy.∴ I&II together are sufficient.