Gravitation

Height of satellite $A$ above Earth's surface: $h_A=1.25 R_E$Height of satellite $B$ above Earth's surface: $h_B=19.25 R_E$Hence,the orbital radii (distance from Earth's center):$\; r_A=R_E+h_A=R_E+1.25 R_E=2.25 R_E$$\; r_B=R_E+h_B=R_E+19.25 R_E=20.25 R_E$Formula for orbital speedFor a satellite in a circular orbit around Earth:$v=\sqrt{\frac{G M_E}{r}}$where $G$ is the gravitational constant and $M_E$ is Earth's mass.Thus, for two satellites $A$ and $B$ :$\frac{v_A}{v_B}=\sqrt{\frac{r_B}{r_A}}$Substitute $r_A$ and $r_B$$\frac{v_A}{v_B}=\sqrt{\frac{20.25 R_E}{2.25 R_E}}=\sqrt{\frac{20.25}{2.25}}=\sqrt{9}=3$Therefore,$v_A : v_B = 3 : 1$