If $\frac{1}{(3 x+1)(x-2)}=\frac{A}{3 x+1}+\frac{B}{x-2}$ and $\frac{x+1}{(3 x+1)(x-2)}=\frac{C}{3 x+1}+\frac{D}{x-2}$, then [AP EAPCET 21 May 2024 Shift 1]

Correct Answer is : A+3B=0,A:C=3:2,B:D=1:3

$A+3 B=0, A: C=1: 3, B: D=2: 3$

$A+3 B=0, A: C=3: 1, B: D=3: 2$

$A-3 B=0, A: C=3: 2, B: D=1: 3$

$A+3 B=0, A: C=3: 2, B: D=1: 3$

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Indefinite Integration

Section: Mathematics

Question : 62

Total: 89

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