Let's determine the color of each aquated ion:(A)Ni2+In aqueous solution:[Ni(H2O)6]2+This complex is green in color. (A)→(V)Green(B)Fe3+In aqueous solution:[Fe(H2O)6]3+This complex is yellow to brownish-yellow. (B)→(III)Yellow(C)Mn3+In aqueous solution:[Mn(H2O)6]3+This complex is violet or red-purple. (C)→(I)Violet(D)V4+In aqueous solution:[VO]2+(vanadyl ion)This species is blue. (D)→(II) Blue Final Matching:A-V, B-I I I, C-I, D-I I Correct Option: D