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AP EAPCET 25-Aug-2021 Shift 2 Paper

Section: Mathematics

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Question : 80

Total: 160

Let y=Y(x) be the solution of the differential equation

+y‌tan‌x=2x+x2‌tan‌x,x∈ (

), such that Y(0)=1, then ______

y(
π
4
)+Y(
−π
4
)=
π2
2
+2
y′(
π
4
)+Y′(
−π
4
)=−√2
y(
π
4
)−Y(
−π
4
)=√2
y′(
π
4
)−Y′(
−π
4
)=π−√2

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