Given equation, 2x3−x2−22x−24=0 Put x=−2 2(−2)3−(−2)2−22(−2)−24 ⇒−16−4+44−24=0 ∴ x+2 is root of equation 2x3−x2−22x−24=0 2x3−x2−22x−24=(x+2)(2x2−5x−12) =(x+2(2x2−8x+3x−14) =(x+2(2x+3)(x−4) ∴ Roots of equation are −2,