Given, wavelength of light, λ=4900Å Stopping potential, V=2V Energy of the incident light, E=
12400‌eV
λÅ
∴ E=
12400
4900
‌eV=2.53‌eV Kinetic energy, KE = Stopping potential × Charge of electron =2×e=2‌eV Using Einstein's photoelectric equation, Kinetic energy = Energy of incident light − Work function 2=2.53−ϕ ⇒ ϕ=2.53−2=0.53‌eV