AP EAPCET 25-Aug-2021 Shift 1 Paper

Given, length of wire, l=3m
Cross-sectional area, A=6.14×10−6m2
Current in the wire, I=6A
Atomic weight of silver =108‌amu
Density of silver, ρ=10500kgm−3
Number of electrons per kg of silver =

NA

108

=

6.023×1023

108

Number of electrons per unit volume of silver.
n=

6.023×1023

108

×10500
Drift current, I=Anevd
where vd is drift velocity and n is number of electrons per unit volume.
⇒ vd=

I

neA

=0.1ms−1