Assertion Given lines r=a+tb and r=p+sq We know that the lines are coplanar if (a−p)⋅(b×q)=0 Thus, the assertion is wrong. Reason The shortest distance between two skew lines is ‌d=‌
|(a−p)⋅(b×q)|
|b×q|
⇒‌‌d|b×q|=|(a−p)⋅(b×q)| Thus, the reason is So, A is false, but R is true.