Given circle, x2+y2−2x+4y−4=0 and x2+y2+4x−6y−3=0 Equation of common chord of circle is S1−S2=0 ∴ (x2+y2−2x+4y−4) −(x2+y2+4x−6y−3)=0 ⇒−6x+10y−1=0 ⇒6x−10y+1=0 Perpendicular distance from the point (1,2) to the line 6x−10y+1=0 is |