Given that atomic mass =1 amu =1.66×10−27‌kg By using Einstein's equation of mass energy relation, E=mc2 where, c= speed of light =3×108m∕s. E=(1.66×10−27)×(3×108)2J =1.494×10−11J We know, 1‌MeV=1.6×10−13J 1J=
1
1.6
×1013‌MeV Substituting the value, we get E=1.494×10−11×