Total outcomes ={1,2,3,4,5,6}=6 Prime number ={2,3,5}=3 So, P(A)=3∕6=1∕2 and even numbers ={2,4,6}=3 ∴P(B)=3∕6=1∕2 Thus, P(B)=1−P(B)=1−1∕2=1∕2 Total sample for 2 throws =6×6=36 Then, P(A∕B)=
P(A∩B)
P(B)
First throw is prime ={2,3,5} Second throw is not even ={1,3,5} Pairs where first is in {2,3,5} and second is in {1,3,5}=3×3=9 outcomes So, P(A∩B)=9∕36=1∕4 Therefore, P(A∕B)=
