The reaction is, 2NaOH+H2SO4→Na2SO4+2H2O Moles of H2SO4 neutralised =‌
0.030
2
= 0.015 moles Initial moles of H2SO4=0.050L×0.5mL =0.025mol Moles of H2SO4 reacted =0.025−0.015=0.010mole Moles of NH3 produced =2×0.010=0.020mole Mass of N =0.020×14=0.28g %‌ of ‌N=‌
