The reaction in which n‌product ‌‌‌≠n‌reactant ‌‌‌ will have ∆H≠∆U So, among the given reactions, in reaction, ‌N2(g)+3H2(g)→2NH3(g) ‌∆U≠∆H ‌‌ As, ‌n‌product ‌=2,n‌reactant ‌=4 ‌∆ng=2−4=−2 ‌∆H=∆U+∆ngRT ‌∆H=∆U−2RT