Given, √x(1−y)+√y(1−x)=1 Let x=sin‌2A and y=sin‌2B ‌⇒√sin‌2A(1−sin‌2B)+√sin‌2B(1−sin‌2A) ‌⇒‌‌sin‌A‌cos‌B+cos‌A‌s‌i‌n‌B=1 ‌⇒‌‌sin‌(A+B)=1=sin‌‌
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‌⇒‌‌A+B=‌
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‌‌...(i) Now, A=sin‌−1√x,B=sin‌−1√y From Eqs. (i), we get sin‌−1√x+sin‌−1√y=‌