‌7‌cos‌θ−sin‌θ=5,tan‌θ>0 ‌7−tan‌θ=5secθ Squaring both sides, we get ⇒49+tan2θ−14‌tan‌θ=25(1+tan2θ) ⇒24tan2θ+14‌tan‌θ−24=0 ⇒12tan2θ+7‌tan‌θ−12=0 ⇒12tan2θ+16‌tan‌θ−9⋅tan‌θ−12=0 ⇒(3‌tan‌θ+4)(4‌tan‌θ−3)=0 ‌tan‌θ=‌