Let P and Q be the points on the given lines where they intersect. P=(1+t,−6+2t,2+t) and Q=(2s,4+s,1+2s) Now, P and Q are identical ∴‌‌t+1‌=2s −6+2t‌=4+s 2+t‌=1+2s On solving Eqs. (i) and (ii), we get s=4‌ and ‌t=7 Which satisfy the Eq. (iii) ∴ Point of intersection (8,8,9) =8