Let's determine the color of each aquated ion: (A)Ni2+ In aqueous solution:[Ni(H2O)6]2+ This complex is green in color. (A)⟶(V)Green (B)Fe3+ In aqueous solution:[Fe(H2O)6]3+ This complex is yellow to brownish-yellow. (B)⟶(III)Yellow (C)Mn3+ In aqueous solution:[Mn(H2O)6]3+ This complex is violet or red-purple. (C)⟶(I)Violet (D)V4+ In aqueous solution:[VO]2+(vanadyl ion)
This species is blue. (D)⟶(II) Blue Final Matching: A−V,‌‌B−III,‌‌C−I,‌‌D−II Correct Option: D